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Free Equation of a Circle Calculator

Write a circle's standard-form equation from its center and radius, or find the center and radius from a general-form equation.

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A circle's standard-form equation, (x−h)²+(y−k)²=r², directly encodes its center (h,k) and radius r — it comes straight from the distance formula, since it says every point (x,y) on the circle is exactly r units from the center (h,k). This calculator converts in both directions — from a known center and radius to the equation, or from a messier general-form equation (x²+y²+Dx+Ey+F=0, the form you'll often get after expanding or from a textbook problem) back to the center and radius, by completing the square on both the x-terms and y-terms.

How it works

Choose a direction. Given the center (h,k) and radius r, the calculator writes the standard-form equation directly by substituting into (x−h)²+(y−k)²=r². Given general-form coefficients from x²+y²+Dx+Ey+F=0, it completes the square on the x-terms and y-terms separately: grouping x²+Dx into (x+D/2)²−(D/2)² and y²+Ey into (y+E/2)²−(E/2)², then moving the constants to the other side. This reveals the center as h = −D/2, k = −E/2, and the radius as r = √(h²+k²−F). If h²+k²−F works out negative, the equation doesn't describe any real circle at all.

  1. Enter direction.
  2. Enter center h.
  3. Enter center k.
  4. Enter radius (r).
  5. Enter d (coefficient of x).
  6. Enter e (coefficient of y).
  7. Enter f (constant).
  8. Click Calculate to see your results.

Examples

Center (2, 3), radius 5

Standard form: (x−2)² + (y−3)² = 25.

General form x² + y² − 4x + 6y − 3 = 0

Here D=−4, E=6, F=−3, so h = −(−4)/2 = 2, k = −6/2 = −3, and r² = 2² + (−3)² − (−3) = 4 + 9 + 3 = 16, giving r = 4. Standard form: (x−2)² + (y+3)² = 16, center (2, −3).

Center (0, 0), radius 7

Standard form: x² + y² = 49 — a circle centered at the origin simplifies since h = k = 0.

Who should use it

  • Converting a textbook general-form circle equation into an easily-graphable standard form.
  • Writing a circle's equation from a known center and radius for a geometry or algebra problem.
  • Checking whether a given quadratic equation actually represents a real circle.

Industry applications

  • Algebra and analytic geometry education
  • Computer graphics and CAD (circle definitions)

Advantages

  • Converts in both directions — center/radius to equation, and equation to center/radius.
  • Shows the completing-the-square work so the conversion isn't a black box.

Limitations

  • Only handles equations of an actual circle — an ellipse or other conic section needs a different approach entirely.

Common mistakes to avoid

  • Forgetting to negate D and E when finding h and k from the general form — the correct relationship is h = −D/2, not h = D/2.
  • Skipping the check for a negative r² result, which signals no real circle exists.
  • Misreading a "+3" inside the parentheses as h = 3 instead of h = −3 — the standard form always subtracts h and k, so a plus sign means the center coordinate itself is negative.

Best practices

  • Always verify your final answer by expanding the standard form back out and checking it matches the original general-form equation.
  • Double check the sign convention when reading h and k directly off a standard-form equation containing a "+" instead of a "−".
  • Watch for a negative r² result as a signal that the given equation has no real circle solution.

Tips

  • Working with a square inscribed in a circle instead? See the Square in a Circle Calculator.

Frequently asked questions

Then the equation doesn't describe a real circle — there's no valid center/radius pair, since a radius can't be the square root of a negative number.
h = −D/2 and k = −E/2 (note the negative sign — this trips people up constantly), then r² = h² + k² − F.
Because x²+Dx and y²+Ey are each "missing" a piece to become a perfect square trinomial; adding and immediately subtracting that missing piece, (D/2)² and (E/2)², rewrites each expression as a squared binomial without changing the equation's value.
It describes a single point (the "circle" has collapsed to zero radius) rather than an actual circle with a visible boundary.
Yes — every circle has exactly one center and one radius, so its standard-form equation is unique, though it can be algebraically rearranged into many different-looking general-form equations depending on how it's expanded.
Yes — the center can be anywhere on the coordinate plane, including negative x or y coordinates; when h or k is negative, the standard form shows a "+" instead of a "−" inside its parentheses, e.g. (x+3)² means h = −3.

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