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Free Half Angle Calculator

Compute sin(θ/2), cos(θ/2), and tan(θ/2) using the half-angle identities, with the ± sign resolved automatically.

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The half-angle identities express sin(θ/2), cos(θ/2), and tan(θ/2) purely in terms of cos(θ) — meaning you can find the sine or cosine of half an angle without ever knowing θ/2's own reference angle. They technically involve a ± sign in their textbook form, since θ/2 could in principle fall in either of two half-planes — but because you give this calculator an exact θ, θ/2 is fully and unambiguously determined, and the correct sign is resolved automatically rather than left for you to figure out. These identities are derived directly from the power-reducing (cosine double-angle) identities by substituting θ/2 in place of θ, and they're commonly used in calculus (certain trig substitutions and integrals simplify only after a half-angle rewrite) and in engineering fields that work with half-wave rectified signals or bisected angles in geometry and design.

How it works

Enter the angle θ. The calculator first finds cos(θ), then applies the half-angle formulas: sin(θ/2) = ±√((1−cosθ)/2) and cos(θ/2) = ±√((1+cosθ)/2), with tan(θ/2) available either as their ratio or via the equivalent identity tan(θ/2) = sinθ/(1+cosθ). To resolve the ambiguous ± sign, the calculator computes θ/2 directly from your input θ and checks which quadrant that half-angle actually falls in, then applies whichever sign (positive or negative) matches sine and cosine's known signs in that quadrant.

  1. Enter angle (θ).
  2. Enter angle unit.
  3. Click Calculate to see your results.

Examples

θ = 60°

sin(60°/2) = sin(30°) = 0.5, matching the half-angle formula √((1−cos60°)/2) = √((1−0.5)/2) = √0.25 = 0.5.

θ = 90°

cos(90°/2) = cos(45°) = √2/2 ≈ 0.7071, matching √((1+cos90°)/2) = √((1+0)/2) = √0.5 ≈ 0.7071.

θ = 120°

sin(120°/2) = sin(60°) ≈ 0.8660, matching √((1−cos120°)/2) = √((1−(−0.5))/2) = √0.75 ≈ 0.8660.

Who should use it

  • Calculus substitutions where a half-angle rewrite simplifies an integral.
  • Trigonometry coursework on the half-angle identities.
  • Geometry problems involving a bisected angle.

Industry applications

  • Calculus and trigonometry education
  • Signal processing (half-wave rectification analysis)

Advantages

  • Resolves the ambiguous ± sign automatically instead of leaving it to you.
  • Works for any angle θ, not just the standard textbook reference angles.

Limitations

  • tan(θ/2) has an undefined edge case when cosθ = −1, which needs special handling.

Common mistakes to avoid

  • Assuming the + sign always applies — it actually depends on which quadrant θ/2 falls in, not which quadrant θ itself is in.
  • Forgetting the square root in the sin(θ/2) and cos(θ/2) formulas and using (1−cosθ)/2 directly as if it were the final answer.
  • Mixing up which formula has the + and which has the − sign inside the square root (cosine uses +cosθ, sine uses −cosθ).

Best practices

  • Compute θ/2 first and identify its quadrant before finalizing the sign, rather than guessing based on θ's own quadrant.
  • Use the sinθ/(1+cosθ) form for tangent when you want to avoid an extra sign decision.
  • Cross-check your half-angle result against a direct evaluation (e.g., using the Sine Calculator on θ/2 itself) when the half-angle happens to be a common reference angle.

Tips

  • Need the reverse operation — going from θ to 2θ — instead? Use the Double Angle Formula Calculator.

Frequently asked questions

sin(θ/2) = ±√((1−cosθ)/2); cos(θ/2) = ±√((1+cosθ)/2); tan(θ/2) = sinθ/(1+cosθ), which avoids a square root and an extra sign decision entirely.
By computing the exact half angle (θ/2) from the given θ and checking which quadrant it lands in, rather than leaving the sign ambiguous the way a bare textbook formula does.
Because the identity is designed to let you find a half-angle's sine or cosine using only the ORIGINAL angle's cosine — that's the entire point of the formula, since it avoids needing θ/2's own reference angle.
They're derived by substituting θ/2 in place of θ in the power-reducing identities (themselves rearranged from the cosine double-angle formula) and then solving for sin(θ/2) or cos(θ/2).
Yes — tan(θ/2) = sinθ/(1+cosθ) (or equivalently (1−cosθ)/sinθ) gives the same result without a square root or a sign ambiguity, which is often more convenient for calculus substitutions.
The tangent half-angle formula sinθ/(1+cosθ) becomes 0/0 in that case, since sin(180°) = 0 and 1+cos(180°) = 0 — this specific case needs to be handled separately or via the square-root form instead.

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