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Free Inverse Variation Calculator

Solve for k, y, or x in an inverse variation relationship xy=k, given the other two values.

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In an inverse variation relationship, written xy=k (equivalently y=k/x), one quantity shrinks as the other grows, in exactly the proportion needed to keep their product constant. Double x and y is cut in half; triple x and y drops to a third of its original value — the two variables move in opposite directions, but always in a fixed, predictable ratio to each other, governed by the constant k. This relationship shows up throughout physics and everyday situations involving a fixed total being divided differently: travel speed and time for a fixed distance vary inversely (drive twice as fast and the trip takes half the time, since speed × time = distance, a constant), and gas pressure and volume at constant temperature follow the same pattern (Boyle's Law) — squeeze a gas into half the volume and its pressure doubles. This tool solves an inverse variation equation xy=k for whichever of the three values — k, x, or y — is unknown, given the other two.

How it works

Given any two of the three values {x, y, k}, the tool finds the third directly from the equation xy=k by rearranging as needed: if x and y are known, k=xy; if k and x are known, y=k/x; if k and y are known, x=k/y. Because the relationship requires the product of x and y to equal k, and division by zero is undefined, neither x nor y can ever be zero in a valid inverse variation with a nonzero k — the tool checks for and rejects such invalid inputs.

  1. Enter solve for.
  2. Enter x (leave blank if solving for x).
  3. Enter y (leave blank if solving for y).
  4. Enter k (leave blank if solving for k).
  5. Click Calculate to see your results.

Examples

Finding the constant of variation

If x=4 and y=3, then k=4×3=12, so y=12/x.

Finding y given k and x

If k=12 and x=6, then y=12/6=2.

Finding x given k and y

If k=20 and y=5, then x=20/5=4, since rearranging xy=k to solve for x gives x=k/y.

Who should use it

  • Algebra coursework on inverse variation and proportional relationships.
  • Word problems involving inversely proportional quantities (e.g. speed and time, or pressure and volume).
  • Checking whether a data set represents an inverse (rather than direct) proportional relationship.

Industry applications

  • Mathematics education
  • Physics (e.g. Boyle's Law-style relationships)

Advantages

  • Solves for any of the three unknowns (k, x, or y).
  • Rejects invalid zero inputs that would make the relationship undefined.
  • Applicable to common physics and real-world inverse relationships.

Limitations

  • Only handles the simple xy=k form, not more complex inverse relationships.

Common mistakes to avoid

  • Assuming x or y can be 0 in an inverse variation — since xy=k with k≠0, neither variable can ever equal zero.
  • Confusing an inverse variation's constant PRODUCT (x×y=k) with a direct variation's constant RATIO (y/x=k) — checking the wrong one leads to a false conclusion about which relationship applies.
  • Assuming inverse variation means "y decreases as x increases" always follows a straight line — it actually follows a curved hyperbola, not a straight line like direct variation.

Best practices

  • Check that a real-world relationship's product (not ratio) stays constant before modeling it as inverse variation.
  • Verify the constant k using more than one data point when possible, to confirm the relationship genuinely holds throughout, not just for one pair.
  • Keep track of units when computing k, since it carries the combined units of x times y.

Tips

  • A quick check for inverse variation in a data table: if every x×y product is the same constant, the relationship is an inverse variation.
  • Remember the graph is a curve (hyperbola), not a straight line — a helpful visual distinction from direct variation.

Frequently asked questions

Speed and travel time for a fixed distance vary inversely — double your speed and the trip takes half as long, since speed × time = distance (a constant).
In direct variation, y=kx, so y increases as x increases; in inverse variation, y=k/x, so y decreases as x increases.
Because xy=k with a nonzero k means neither factor can be zero (since anything multiplied by zero is zero, not k) — and solving for x or y would require dividing by zero, which is undefined.
Check whether the product x×y is the same constant value for every pair of data points — if it is, the relationship is inverse variation; direct variation would instead show a constant ratio y/x, not product.
Yes — a negative k still describes an inverse variation, just with x and y having opposite signs from each other (since their product must equal the negative constant).
It forms a hyperbola, curving away from both axes and never actually touching either the x-axis or y-axis, since neither variable can equal zero.

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