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Free Consecutive Integers Calculator

Solve for the starting integer given a sum and count of consecutive integers, or list a sequence and its sum given a start.

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Key Features

Instant Calculation

Get accurate results in real time with our optimized algorithm.

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Consecutive integer problems are a classic staple of introductory algebra: "the sum of three consecutive integers is 24 — what are the three numbers?" These problems are popular in textbooks because they're a clean, concrete way to practice translating a word problem into an algebraic equation — letting the first integer be some unknown n, then expressing the rest as n+1, n+2, and so on, before solving for n. This tool solves that classic direction — finding the starting integer (and the full sequence) given a target sum and a count of integers — or runs the calculation in reverse, listing a sequence and computing its sum given just a starting integer and how many consecutive integers to include.

How it works

The sum of n consecutive integers starting at s follows a direct formula: n×s + n(n−1)/2 — this comes from adding s + (s+1) + (s+2) + ... up to n terms, and simplifying using the standard sum-of-consecutive-numbers pattern. Given a target sum and count, the tool solves this formula algebraically for s. Given a starting integer and count instead, the tool simply plugs both values into the formula directly to compute the sum, then lists out the full sequence of integers involved.

  1. Enter given.
  2. Enter sum (if mode is "from sum").
  3. Enter starting integer (if mode is "from start").
  4. Enter count of consecutive integers.
  5. Click Calculate to see your results.

Examples

Solving for the start

Three consecutive integers summing to 24: solving gives a starting integer of 7, so the sequence is 7, 8, 9 (7+8+9 = 24).

Solving for a longer sequence

Five consecutive integers summing to 100: solving gives a starting integer of 18, so the sequence is 18, 19, 20, 21, 22 (which indeed sums to 100).

Working forward from a known start

Starting at 12 with a count of 4 consecutive integers gives the sequence 12, 13, 14, 15, with a sum of 54 — the reverse direction, useful when you already know where a sequence begins.

Who should use it

  • Solving classic algebra word problems about consecutive integers.
  • Quickly generating a sequence and its sum for a known starting point.
  • Checking homework answers for consecutive integer problems.

Industry applications

  • Education (algebra coursework)
  • Puzzle and recreational mathematics

Advantages

  • Solves in both directions: sum-and-count to sequence, or start-and-count to sum.
  • Lists the full resulting sequence, not just the starting value.
  • Clearly flags when no integer solution exists.

Limitations

  • Only handles consecutive integers (step of 1) — not consecutive even/odd numbers or other fixed-step sequences.

Common mistakes to avoid

  • Assuming every sum is achievable with any chosen count of consecutive integers — some combinations simply have no integer solution.
  • Setting up the word problem's equation incorrectly, such as forgetting to add all n terms or mislabeling the count of integers involved.
  • Confusing consecutive integers (step of 1) with consecutive even or odd integers (step of 2), which need a different formula.

Best practices

  • When solving consecutive integer word problems by hand, set up the algebraic sum formula first rather than guessing and checking.
  • Double check your answer by adding the resulting sequence back together to confirm it matches the target sum.
  • For even/odd consecutive integer problems, adjust your formula's step size before relying on standard consecutive-integer logic.

Tips

  • For consecutive even or odd integers (step of 2), adjust the count-related terms in the formula accordingly — this tool is specifically for step-1 consecutive integers.
  • Always verify your final sequence by adding it up manually as a sanity check.

Frequently asked questions

Not every (sum, count) combination has a solution in whole integers — the tool checks this and explains when no such sequence exists.
Yes — consecutive integer sequences can start at any integer, including negative numbers or zero.
Because solving the sum formula for the starting integer s can produce a non-integer result for certain combinations of sum and count — since consecutive integer sequences by definition must start at a whole number, a fractional result means no valid sequence exists.
No — this tool is specifically built for standard consecutive integers with a step of 1; consecutive even or odd integers use a step of 2, which requires an adjusted version of the sum formula.
Let the first integer be an unknown n, express the rest as n+1, n+2, and so on for however many terms the problem describes, add them all together, set the total equal to the given sum, and solve for n — this tool automates exactly that process.
For a valid sum-and-count combination, yes — there's exactly one starting integer that produces that sum for that count, since the sum formula is linear in the starting value.

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